🔗LC2666 🟢 Easy 🧩 Pattern – Function Transformations
📅 Day 10/30 Days of JavaScript
Given a function fn
, return a new function that is identical to the original function except that it ensures fn
is called at most once.
- The first time the returned function is called, it should return the same result as
fn
. - Every subsequent time it is called, it should return
undefined
.
Example
Input: fn = (a,b,c) => (a + b + c), calls = [[1,2,3],[2,3,6]]
Output: [{"calls":1,"value":6}]
Explanation:
const onceFn = once(fn);
onceFn(1, 2, 3); // 6
onceFn(2, 3, 6); // undefined, fn was not called
Solution
/**
* @param {Function} fn
* @return {Function}
*/
var once = function (fn) {
let isCalled = false
return function (...args) {
if (!isCalled) {
isCalled = true;
return fn(...args)
}
return undefined;
}
};
/**
* let fn = (a,b,c) => (a + b + c)
* let onceFn = once(fn)
*
* onceFn(1,2,3); // 6
* onceFn(2,3,6); // returns undefined without calling fn
*/