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10 Ways to iterate through an array in JavaScript

10 Ways to iterate through an array in JavaScript

In this post we will explore all the ways we can iterate through an array in JavaScript. Let’s loop! 🔄

Standard ways

  • forEach
  • for…of
  • for…in
  • for
  • while

Other ways – here the goal is to not iterate but get results from array data

  • map
  • filter
  • reduce
  • some
  • every

Different ways to iterate a JS array

const arr = [1, 2, 3, 4, 5];

// forEach - iterates through each value.
arr.forEach((n, index) => console.log("forEach", n, "index", index));

// for...of loop - iterates through each value.
for (n of arr) {
  console.log("for...of", n);
}

// for...in loop - iterates through each index.
for (n in arr) {
  console.log("for...in", arr[n]);
}

// for loop - iterates through each index.
for (let i = 0; i < arr.length; i++) {
  console.log("for loop", arr[i]);
}

// while loop - iterates through each index.
let j = 0;
while (j < arr.length) {
  console.log("while loop", arr[j]);
  j++;
}Code language: JavaScript (javascript)

Other ways to process array values

const arr = [1, 2, 3, 4, 5];

// map - used to transform existing values and create a new array
const newArr = arr.map((n, index) => {
  console.log("map", n, "index", index);
  return n * 2;
});
console.log("newArr", newArr); //  [2,4,6,8,10]

// filter - filter required values
const filtered = arr.filter((n, index) => {
  console.log("filter", n, "index", index);
  return n % 2 === 0;
});
console.log("filtered", filtered); // [2,4]

// reduce - acumulate all values
const sum = arr.reduce((acc, n, index) => {
  console.log("reduce", n, "index", index);
  return acc + n;
}, 0);
console.log("sum", sum); // 15

// some - check if atleast one element pass the test
// Stops running if one element pass the test
const some = arr.some((n, index) => {
  console.log("some", n, "index", index);
  if (n % 2 === 0) {
    return true;
  }
});
console.log("some", some); // true

// every - check if all elements pass the test
// Stops running if one element fails the test
const every = arr.every((n, index) => {
  console.log("every", n, "index", index);
  if (n % 2 === 0) {
    return true;
  }
});
console.log("every", every); // false
Code language: JavaScript (javascript)
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